In a compound oxide ion have ccp arrangement, cations A are present in $\frac{1}{8}$ of the tetrahedral voids and cations B occupy $\frac{1}{2}$ of the octahedral voids. What are the formula of the compound?

• A

  ${\mathrm{A}}_2\mathrm{B}{\mathrm{O}}_4$
• Correct answer
  B

  $\mathrm{A}{\mathrm{B}}_2{\mathrm{O}}_4$
• C

  $\mathrm{A}\mathrm{B}{\mathrm{O}}_2$
• D

  ${\mathrm{A}}_2\mathrm{B}{\mathrm{O}}_2$

Hence, the correct answer is option: 'B'.