Q52 / 200 · NEET 2011 (Screening) · Chemistry

Standard electrode potential of three metals $X, Y$ and $Z$ are $-1.2 \mathrm{~V},+0.5 \mathrm{~V}$ and $-3.0 \mathrm{~V}$ respectively. The reducing power of these metals will be

  • A
    $Y>X>Z$
  • Correct answer
    B
    $Z>X>Y$
  • C
    $X>Y>Z$
  • D
    $Y>Z>X$

Solution

$$ \begin{aligned} & E_X^{\circ}=-1.2 \mathrm{~V} \\ & E_Y^{\circ}=+0.5 \mathrm{~V} \\ & E_Z^{\circ}=-3.0 \mathrm{~V} \\ & \therefore Z>X>Y[\because \text { higher the reduction potential, } \end{aligned} $$ lesser the reducing power.

Hence, the correct answer is option: 'B'.

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