Q80 / 200 · NEET 2022 (Phase 2) · Chemistry

Shown below are adsorption isotherms for a gas ' $\mathrm{X}$ ' at temperatures $\mathrm{T}_1, \mathrm{~T}_2$ and $\mathrm{T}_3$ : Figure
$p$ and $\frac{x}{m}$ represent pressure and extent of adsorption, respectively. The correct order of temperatures for the given adsorption is:

  • A
    $\mathrm{T}_1>\mathrm{T}_2>\mathrm{T}_3$
  • Correct answer
    B
    $\mathrm{T}_3>\mathrm{T}_2>\mathrm{T}_1$
  • C
    $\mathrm{T}_1=\mathrm{T}_2=\mathrm{T}_3$
  • D
    $\mathrm{T}_1=\mathrm{T}_2>\mathrm{T}_3$

Solution

'$x$' is mass of gas adsorbed on mass ' $m$ ' of the adsorbent at pressure ' $p$ '. The curves in the given adsorption isotherm indicates that at a fixed pressure, there is decrease in physical adsorption with increase in temperature and vice versa. So, the correct order of temperature is : $\mathrm{T}_3>\mathrm{T}_2>\mathrm{T}_1$

Hence, the correct answer is option: 'B'.

More Surface Chemistry Questions