Q66 / 90 · KVPY 2012 (SB/SX) · Physics
Seven identical coins are rigidly arranged on a flat table in the pattern shown below so that each coin touches its neighbors. Each coin is a thin disc of mass $\mathrm{m}$ and radius $\mathrm{r}$. Note that the moment of inertia of an individual coin about an axis passing through centre and perpendicular to the plane of the coin is $\mathrm{mr}^{2} / 2$

The moment of inertia of the system of seven coins about an axis that passes through the point $\mathrm{P}$ (the centre of the coin positioned directly to the right of the central coin) and perpendicular to the plane of the coins is-

The moment of inertia of the system of seven coins about an axis that passes through the point $\mathrm{P}$ (the centre of the coin positioned directly to the right of the central coin) and perpendicular to the plane of the coins is-
- A$\frac{55}{2} \mathrm{mr}^{2}$
- B$\frac{127}{2} \mathrm{mr}^{2}$
- Correct answerC$\frac{111}{2} \mathrm{mr}^{2}$
- D$55 \mathrm{mr}^{2}$
Solution
By using parallel axis theorem, $\mathrm{I}=\frac{111}{2} \mathrm{mr}^{2}$
Hence, the correct answer is option: 'C'.