Q66 / 90 · KVPY 2012 (SB/SX) · Physics

Seven identical coins are rigidly arranged on a flat table in the pattern shown below so that each coin touches its neighbors. Each coin is a thin disc of mass $\mathrm{m}$ and radius $\mathrm{r}$. Note that the moment of inertia of an individual coin about an axis passing through centre and perpendicular to the plane of the coin is $\mathrm{mr}^{2} / 2$ Figure
The moment of inertia of the system of seven coins about an axis that passes through the point $\mathrm{P}$ (the centre of the coin positioned directly to the right of the central coin) and perpendicular to the plane of the coins is-

  • A
    $\frac{55}{2} \mathrm{mr}^{2}$
  • B
    $\frac{127}{2} \mathrm{mr}^{2}$
  • Correct answer
    C
    $\frac{111}{2} \mathrm{mr}^{2}$
  • D
    $55 \mathrm{mr}^{2}$

Solution

By using parallel axis theorem, $\mathrm{I}=\frac{111}{2} \mathrm{mr}^{2}$

Hence, the correct answer is option: 'C'.

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