A train is moving slowly at 2 m/s next to a railway platform. A man, 1.5 m tall, alights from the train such that his feet are fixed on the ground…

Question

A train is moving slowly at 2 m/s next to a railway platform. A man, 1.5 m tall, alights from the train such that his feet are fixed on the ground. Taking him to be a rigid body, the instantaneous angular velocity (in rad/s) is

MARKS Content Team · Accepted Answer

Correct answer: (B) 2.0. As man alight, its angular momentum about a point on platform is conserved. By angular momentum conservation, L_initial=L_final⇒mvr=Iω ⇒mvr=(ml^2)/3·ω⇒(3vrl^2=ω or ω=3×2×1.5)/21.5^2=2 rad/s So, instantaneous angular speed of man =2 rad/s.

A train is moving slowly at $2 m / s$ next to a railway platform. A man, $1.5 m$ tall, alights from the train such that his feet are fixed on the ground. Taking him to be a rigid body, the instantaneous angular velocity (in $rad / s$ ) is

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