Q12 / 180 · COMEDK 2013 · Chemistry

Same amount of electric current is passed through solutions of $\mathrm{AgNO}_{3}$ and $\mathrm{HCl}$. If $1.08 \mathrm{~g}$ of silver is obtained in the first case, the amount of hydrogen liberated at STP in the second case is

  • A
    $224 \mathrm{~cm}^{3}$
  • B
    $1.008 \mathrm{~g}$
  • Correct answer
    C
    $112 \mathrm{~cm}^{3}$
  • D
    $22400 \mathrm{~cm}^{3}$

Solution

If current is same then, $$ \begin{aligned} &E_{\mathrm{wt}} \text { of } \mathrm{Ag}=E_{\mathrm{w}} \text { of } \mathrm{H}_{2} \\ &\quad \frac{1.08}{108}=\frac{x}{1} \\ &\therefore \quad \text { Mass of } \mathrm{H}_{2}, x=10^{-2} \mathrm{~g} \\ &\therefore \quad 2 \mathrm{~g} \text { of } \mathrm{H}_{2} \text { at } \mathrm{STP} \text { occupy } 22400 \mathrm{~cm}^{3} \\ &\therefore \quad 10^{-2} \mathrm{~g} \text { of } \mathrm{H}_{2} \text { at STP occupy } \\ &\quad=\frac{22400}{2} \times 10^{-2} \mathrm{~cm}^{3}=112 \mathrm{~cm}^{3} \end{aligned} $$

Hence, the correct answer is option: 'C'.

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