Q11 / 180 · COMEDK 2013 · Chemistry
A galvanic cell is constructed using the redox reaction,
$\frac{1}{2} \mathrm{H}_{2}(g)+\operatorname{AgCl}(s) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{Cl}^{-}(a q)+\operatorname{Ag}(s)$
it is represented as
- A$\mathrm{Pt}\left|\mathrm{H}_{2}(g)\right| \mathrm{HCl}(\mathrm{sol})|| \mathrm{AgNO}_{3}(\mathrm{sol}) \mid \mathrm{Ag}$
- B$\operatorname{Ag}|\operatorname{AgCl}(s)| \mathrm{KCl}(\mathrm{sol})|| \mathrm{HCl}(\mathrm{sol}), \mathrm{H}_{2}(\mathrm{~g}) \mid \mathrm{Pt}$
- C$\mathrm{Pt}\left|\mathrm{H}_{2}(g)\right| \mathrm{KCl}(\operatorname{sol}) \| \operatorname{AgCl}(s) \mid \mathrm{Ag}$
- Correct answerD$\mathrm{Pt}\left|\mathrm{H}_{2}(g), \mathrm{HCl}(\operatorname{sol})\right||\operatorname{AgCl}(s)| \mathrm{Ag}$
Solution
At anode, oxidation occurs of $\mathrm{H}_{2}$ (gas), while at cathode reduction of $\mathrm{AgCl}$ take place.
$\therefore$ The cell notation is
$\mathrm{Pt}\left|\mathrm{H}_{2}(\mathrm{~g}), \mathrm{HCl}(\mathrm{sol}) \| \mathrm{AgCl}(s)\right| \mathrm{Ag}$
Hence, the correct answer is option: 'D'.