Q18 / 69 · JEE Advanced 2011 (Paper 1) · Chemistry

Reaction of $\mathrm{Br}_2$ with $\mathrm{Na}_2 \mathrm{CO}_3$ in aqueous solution gives sodium bromide and sodium bromate with evolution of $\mathrm{CO}_2$ gas. The number of sodium bromide molecules involved in the balanced chemical equation is

Correct answer: 5

Solution

$\mathrm{Br}_2$ is disproportionated in basic medium as $$ 3 \mathrm{Br}_2+3 \mathrm{Na}_2 \mathrm{CO}_3 \longrightarrow 5 \mathrm{NaBr}+\mathrm{NaBrO}_3+3 \mathrm{CO}_2 $$

Hence, the correct answer is 5.

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