Q2 / 51 · JEE Advanced 2024 (Paper 1) · Chemistry
At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid $\left(\mathrm{HNO}_2\right)$ gives the species
- Correct answerA$\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}$and $\mathrm{NO}$
- B$\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3{ }^{-}$and $\mathrm{NO}_2$
- C$\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}^{-}$and $\mathrm{NO}_2$
- D$\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3{ }^{-}$and $\mathrm{N}_2 \mathrm{O}$
Solution
$3 \mathrm{HNO}_2(\mathrm{aq}) \rightleftharpoons \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{NO}_3^{-}+2 \mathrm{NO}$
Hence, the correct answer is option: 'A'.