Q2 / 51 · JEE Advanced 2024 (Paper 1) · Chemistry

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid $\left(\mathrm{HNO}_2\right)$ gives the species

  • Correct answer
    A
    $\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}$and $\mathrm{NO}$
  • B
    $\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3{ }^{-}$and $\mathrm{NO}_2$
  • C
    $\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}^{-}$and $\mathrm{NO}_2$
  • D
    $\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3{ }^{-}$and $\mathrm{N}_2 \mathrm{O}$

Solution

$3 \mathrm{HNO}_2(\mathrm{aq}) \rightleftharpoons \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{NO}_3^{-}+2 \mathrm{NO}$

Hence, the correct answer is option: 'A'.

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