Q16 / 180 · COMEDK 2018 · Chemistry
$\Delta G^{\circ} v s \dddot{l}$ plot in the Eliingham's diagram, slopes downwards for the reaction
- A$\mathrm{Mg}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{MgO}$
- B$2 \mathrm{Ag}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{Ag}_{2} \mathrm{O}$
- Correct answerC$\mathrm{C}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{CO}$
- D$\mathrm{CO}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}$
Solution
For the reaction, $\mathrm{C}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{CO}$,
$\Delta G^{\circ}$ vs $T$ plot in the Ellingham's diagram slopes downwards.
As for this reaction $\Delta G^{\circ}$ become more negative with increase in temperature.
Hence, the correct answer is option: 'C'.