Q105 / 120 · JEE Advanced 2006 · Physics

Paragraph: Two plane harmonic sound waves are expressed by the equations. $$ \begin{aligned} & y_1(x, t)=A \cos (0.5 \pi x-100 \pi t) \\ & y_2(x, t)=A \cos (0.46 \pi x-92 \pi t) \end{aligned} $$ (All parameters are in MKS)Question: How many times does an observer hear maximum intensity in one second?

  • Correct answer
    A
    4
  • B
    10
  • C
    6
  • D
    8

Solution

In one second number of maximas is called the beat frequency. Hence, $$ f_b=f_1-f_2=\frac{100 \pi}{2 \pi}-\frac{92 \pi}{2 \pi}=4 \mathrm{~Hz} $$

Hence, the correct answer is option: 'A'.

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