Q105 / 120 · JEE Advanced 2006 · Physics
Paragraph:
Two plane harmonic sound waves are expressed by the equations.
$$
\begin{aligned}
& y_1(x, t)=A \cos (0.5 \pi x-100 \pi t) \\
& y_2(x, t)=A \cos (0.46 \pi x-92 \pi t)
\end{aligned}
$$
(All parameters are in MKS)Question:
How many times does an observer hear maximum intensity in one second?
- Correct answerA4
- B10
- C6
- D8
Solution
In one second number of maximas is called the beat frequency. Hence,
$$
f_b=f_1-f_2=\frac{100 \pi}{2 \pi}-\frac{92 \pi}{2 \pi}=4 \mathrm{~Hz}
$$
Hence, the correct answer is option: 'A'.