Q15 / 69 · JEE Advanced 2008 (Paper 1) · Chemistry

Paragraph: In the following reaction sequence, product $I . J$ and $L$ are formed. K represent a reagentFigure
Question: The structure of the product $I$ isFigure

  • A
    Figure
  • B
    Figure
  • C
    Figure
  • Correct answer
    D
    Figure

Solution

$\mathrm{NaBH}_4$ reduces $-\mathrm{CHO}$ selectively into $-\mathrm{CH}_2 \mathrm{OH}$, which is further converted into corresponding bromide by $\mathrm{PBr}_3$ without affecting the triple bond.

Hence, the correct answer is option: 'D'.

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