Q19 / 66 · JEE Advanced 2008 (Paper 2) · Chemistry
Paragraph:
A tertiary alcohol $H$ upon acid catalysed dehydration gives a product $I$. Ozonolysis of I leads to compounds $\mathrm{J}$ and $\mathrm{K}$. Compound $\mathrm{J}$ upon reaction with
$\mathrm{KOH}$ gives benzyl alcohol and a compound $\mathrm{L}$, where $\mathrm{K}$ on reaction with $\mathrm{KOH}$ gives only $M$.
Question:
The structures of compounds $J, K$ and $L$, respectively, are

Question: The structures of compounds $J, K$ and $L$, respectively, are
- A$\mathrm{PhCOCH}_3, \mathrm{PhCH}_2 \mathrm{COCH}_3$ and $\mathrm{PhCH}_2 \mathrm{COO}^{-} \mathrm{K}^{+}$
- B$\mathrm{PhCHO}, \mathrm{PhCH}_2 \mathrm{CHO}$ and $\mathrm{PhCH}_2 \mathrm{COO}^{-} \mathrm{K}^{+}$
- C$\mathrm{PhCOCH}_3, \mathrm{PhCH}_2 \mathrm{CHO}$ and $\mathrm{CH}_3 \mathrm{COO}^{-} \mathrm{K}^{+}$
- Correct answerD$\mathrm{PhCHO}, \mathrm{PhCOCH}_3$ and $\mathrm{PhCOO}^{-} \mathrm{K}^{+}$
Solution
$$
J=\mathrm{PhCH}=\mathrm{O} K=\mathrm{PhCOCH}_3 \quad L=\mathrm{PhCOO}^{-} \mathrm{K}^{+}
$$
Hence, the correct answer is option: 'D'.