Q15 / 60 · JEE Advanced 2009 (Paper 1) · Chemistry
Paragraph:
A carbonyl compound $P$, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin $Q$. Ozonolysis of $Q$ leads to a dicarbonyl compound $R$, which undergoes intramolecular aldol reaction to give predominantly $S$.
$$
P \underset{\text { (ii) } \mathrm{H}^{+}, \mathrm{H}_2 \mathrm{O}}{\stackrel{\text { (i) } \mathrm{MeMgBr}}{\longrightarrow}} \mathrm{Q} \underset{\text { Heat }}{\stackrel{\mathrm{O}_3 / \mathrm{Zn}-\mathrm{H}_2 \mathrm{O}}{\longrightarrow}} \mathrm{P}
$$
(iii) $\mathrm{H}_2 \mathrm{SO}_4$ /HeatQuestion:
$$
\text { The structure of the product } S \text {, is }
$$
- A

- Correct answerB

- C

- D

Hence, the correct answer is option: 'B'.