Q14 / 160 · TS EAMCET 2022 (20 Jul Shift 2) · Chemistry

$\mathrm{CaC}_2+2 \mathrm{D}_2 \mathrm{O} \longrightarrow$ "P" $+\mathrm{Ca}(\mathrm{OD})_2$ In the above reaction product " $\mathrm{P}$ " is

  • A
    $\mathrm{C}_2 \mathrm{H}_2$
  • B
    $\mathrm{C}_2 \mathrm{H}_4$
  • C
    $\mathrm{CD}_4$
  • Correct answer
    D
    $\mathrm{C}_2 \mathrm{D}_2$

Solution

$\mathrm{CaC}_2+2 \mathrm{D}_2 \mathrm{O} \rightarrow \mathrm{Ca}(\mathrm{OD})_2+\mathrm{C}_2 \mathrm{D}_2$

Hence, the correct answer is option: 'D'.

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