Q28 / 155 · WBJEE 2018 · Chemistry

Out of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one?

  • A
    $(n-1) d^{8} n s^{2}$
  • Correct answer
    B
    $(n-1) d^{5} n s^{2}$
  • C
    $(n-1) d^{3} n s^{2}$
  • D
    $(n-1) d^{5} n s^{1}$

Solution

Out of the given outer electronic configuration of atoms, the highest oxidation state is achieved by $(n-1) d^{5} n s^{2}$ i.e. 7 A large number of oxidation state is due to the fact the $(n-1) d$ -electrons may get involved along with $n s$ electrons in bonding as electrons in $(n-1) d-$ orbitals are in an energy state comparable to $n s$ -electrons. Oxidation state of other options are as follows: Figure

Hence, the correct answer is option: 'B'.

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