Q166 / 225 · JEE Main 2004 · Physics

One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively $\mathrm{I}_{\mathrm{A}}$ and $\mathrm{I}_{\mathrm{B}}$ such that

  • A
    $I_A=I_B$
  • B
    $I_A>I_B$
  • Correct answer
    C
    $I_A < I_B$
  • D
    yes, $45^{\circ}$ $I_A / I_B=d_A / d_B$ Where $d_A$ and $d_B$ are their densities.

Solution

Moment of inertia of a uniform density solid sphere, $A=\frac{2}{5} M R^2$ Since $M$ and $R$ are same, $I_A < I_B$.

Hence, the correct answer is option: 'C'.

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