Q23 / 90 · JEE Main 2012 (12 May Online) · Chemistry

$5 \mathrm{~g}$ of benzene on nitration gave $6.6 \mathrm{~g}$ of nitrobenzene. The theoretical yield of the nitrobenzene will be

  • A
    $4.5 \mathrm{~g}$
  • B
    $5.6 \mathrm{~g}$
  • Correct answer
    C
    $8.09 \mathrm{~g}$
  • D
    $6.6 \mathrm{~g}$

Solution

$\mathrm{C}_6 \mathrm{H}_6+\mathrm{HNO}_3 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{NO}_2+\mathrm{H}_2 \mathrm{O}$ $78 \mathrm{~g} \quad 123 \mathrm{~g}$ Now since $78 \mathrm{~g}$ of benzene on nitration give $=123 \mathrm{~g}$ nitrobenzene hence $5 \mathrm{~g}$ of benzene on nitration give $=\frac{123}{78} \times 5=7.88 \mathrm{~g}$ nearest answer is (c) i.e. theoritical yield $=7.88 \mathrm{~g}$

Hence, the correct answer is option: 'C'.

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