Match the following:
The correct answer is

(A) Oxidation state of $\mathrm{VOCl}_2$ is +4 . Oxidation state of $\mathrm{V}=x$ $$ \begin{array}{rlrl} & & x-2-2 & =0 \\ \Rightarrow & x & =+4 \end{array} $$
Thus, (A) is correct match with (V). (B)
Oxidation state of $\mathrm{Mn}=x$ $$ \begin{gathered} x-8=-2 \\ x=+6 \\ \mathrm{Mn}^{+6} \longrightarrow[\mathrm{Ar}] 3 d^1 4 s^0 \end{gathered} $$ $\mathrm{Mn}^{+6}$ contains one unpaired electron in $d$-subshell. Hence, (B) is correct match with (II).
Oxidation state of $\mathrm{Ni}=x$ $$ \begin{aligned} x-4 & =-2 \\ x & =+2 \end{aligned} $$ $$ \mathrm{Ni}^{2+} \rightarrow[\mathrm{Ar}] 3 d^8 4 s^0 $$ $\mathrm{Ni}^{2+}$ has two unpaired electron in $d$-subshell. Thus, (C) is correct match with (VI). (D) Lanthanide ions exhibited by oxidation state equal to +3 . Hence, (D) is correct match with (IV).