Q31 / 160 · TS EAMCET 2024 (09 May Shift 1) · Chemistry
The molecular formula of a coordinate complex is $\mathrm{COH}_{12} \mathrm{O}_6 \mathrm{Cl}_3$. When one mole of this aqueous solution of complex is reacted with excess of aqueous $\mathrm{AgNO}_3$ solution, three moles of AgCl was formed. What is the correct formula of the complex?
- Correct answerA$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$
- B$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}^{-} \mathrm{Cl}_2 \mathrm{H}_2 \mathrm{O}\right.$
- C$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \stackrel{2}{\mathrm{Cl}}\left(\mathrm{H}_2 \mathrm{O}\right)_2$
- D$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{Cl}_3\right]\left(\mathrm{H}_2 \mathrm{O}\right)_3$
Solution
$\begin{aligned} & \left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3 \rightarrow\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}+\mathrm{Cl}^{-} \\ & 3 \mathrm{Ag}^{+}+3 \mathrm{Cl}^{-} \rightarrow 3 \mathrm{AgCl}^{-}(\mathrm{s})\end{aligned}$
Hence, the correct answer is option: 'A'.