Q10 / 200 · MHT CET - Medical 2026 (24 April Shift 2) · Biology

Match the disorders in List I with their causes in List II and choose the correct option.
List IList II
(A) Thalassemia.(I) non-disjunction of sex chromosomes.
(B) Sickle-cell anaemia.(II) non-disjuction of 21st pair of chromosomes.
(C) Turner's Syndrome.(III) Synthesising few globin molecules.
(D) Down's Syndrome.(IV) synthesising an incorrectly functional globin.

  • A
    (A) - (I), (B) - (II), (C) - (III), (D) - (IV).
  • B
    (A) - (II), (B) - (IV), (C) - (I), (D) - (III).
  • C
    (A) - (I), (B) - (II), (C) - (IV), (D) - (III).
  • Correct answer
    D
    (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Solution

Thalassemia is a quantitative blood disorder that results in the synthesis of too few globin molecules. Thus, (A) matches (III).

Sickle-cell anaemia is a qualitative blood disorder that results in the synthesis of an incorrectly functioning globin molecule. Thus, (B) matches (IV).

Turner's Syndrome is caused by the absence of one of the X chromosomes ($45$ with $X0$), which occurs due to the non-disjunction of sex chromosomes during gametogenesis. Thus, (C) matches (I).

Down's Syndrome is caused by the presence of an additional copy of chromosome number $21$ (trisomy of $21$), which occurs due to the non-disjunction of the $21$st pair of chromosomes. Thus, (D) matches (II).

The correct matching is (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Answer: (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Hence, the correct answer is option: 'D'.

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