Q192 / 200 · NEET 2023 (Manipur) · Zoology

Match List-I with List-II. Figure
Choose the correct answer from the options given below.

  • A
    $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$
  • B
    $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$
  • Correct answer
    C
    $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
  • D
    $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$

Solution

Option (3) is the answer because, Kanamycin is an antibiotic which can be used as selectable marker for $E$. coli. Clal is a restriction site on plasmid pBR322. Disarmed retroviruses are used to deliver genes into animal cells, which is an indirect method of gene transfer. Kanamycin ${ }^R$ gene exhibits resistance against kanamycin which is an antibiotic.

Hence, the correct answer is option: 'C'.

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