Q17 / 75 · JEE Main 2026 (02 April Shift 1) · Chemistry

Match List - I with List - II.
List - I
Mixture of Compounds
List - II
Reagent used to distinguish
A. Diethyl amine + Ethyl amineI. Bromine water
B. Acetaldehyde + AcetoneII. $CHCl_3 + KOH, \Delta$
C. Ethanol + PhenolIII. Neutral $FeCl_3$
D. Benzoic acid + Cinnamic acidIV. Ammonical silver nitrate

Choose the correct answer from the options given below :

  • A
    A-IV, B-II, C-I, D-III
  • B
    A-IV, B-II, C-III, D-I
  • C
    A-II, B-IV, C-I, D-III
  • Correct answer
    D
    A-II, B-IV, C-III, D-I

Solution

Diethyl amine is a secondary amine and ethyl amine is a primary amine. Primary amines give the carbylamine test with $CHCl_3$ and $KOH$ on heating, while secondary amines do not. Thus, A matches with II.

Acetaldehyde is an aldehyde and acetone is a ketone. Aldehydes reduce ammoniacal silver nitrate (Tollens' reagent) to form a silver mirror, while ketones do not. Thus, B matches with IV.

Phenol reacts with neutral $FeCl_3$ to form a violet-colored complex, whereas ethanol does not react. Thus, C matches with III.

Cinnamic acid contains a carbon-carbon double bond which decolorizes bromine water, whereas benzoic acid does not react with bromine water. Thus, D matches with I.

The correct matching is A-II, B-IV, C-III, D-I.

Answer: A-II, B-IV, C-III, D-I

Hence, the correct answer is option: 'D'.

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