Q3 / 75 · JEE Main 2026 (22 January Shift 2) · Chemistry
Match List - I with List - II.
$\begin{array}{l} \text{List - I} & \text{List - II} \\ \text{Reaction of Glucose with} & \text{Product formed} \\ \text{A. Hydroxylamine} & \text{I. Gluconic acid} \\ \text{B. } \mathrm{Br}_{2} \text{ water} & \text{II. Glucose pentacetate} \\ \text{C. Excess acetic anhydride} & \text{III. Saccharic acid} \\ \text{D. Concentrated } \mathrm{HNO}_{3} & \text{IV. Glucoxime} \end{array}$
Choose the correct answer from the options given below :
$\begin{array}{l} \text{List - I} & \text{List - II} \\ \text{Reaction of Glucose with} & \text{Product formed} \\ \text{A. Hydroxylamine} & \text{I. Gluconic acid} \\ \text{B. } \mathrm{Br}_{2} \text{ water} & \text{II. Glucose pentacetate} \\ \text{C. Excess acetic anhydride} & \text{III. Saccharic acid} \\ \text{D. Concentrated } \mathrm{HNO}_{3} & \text{IV. Glucoxime} \end{array}$
Choose the correct answer from the options given below :
- AA-III, B-I, C-IV, D-II
- BA-I, B-III, C-IV, D-II
- CA-IV, B-III, C-II, D-I
- Correct answerDA-IV, B-I, C-II, D-III
Solution
Glucose reactions: A + Hydroxylamine forms glucoxime (IV) via condensation with aldehyde group.
B + Br₂ water oxidizes aldehyde to carboxylic acid, forming gluconic acid (I).
C + Excess acetic anhydride acetylates all hydroxyl groups to form glucose pentaacetate (II).
D + Concentrated HNO₃ oxidizes both aldehyde and primary alcohol groups to form saccharic acid (III).
The correct matching is A-IV, B-I, C-II, D-III.
B + Br₂ water oxidizes aldehyde to carboxylic acid, forming gluconic acid (I).
C + Excess acetic anhydride acetylates all hydroxyl groups to form glucose pentaacetate (II).
D + Concentrated HNO₃ oxidizes both aldehyde and primary alcohol groups to form saccharic acid (III).
The correct matching is A-IV, B-I, C-II, D-III.
Hence, the correct answer is option: 'D'.