Q13 / 90 · JEE Main 2024 (06 Apr Shift 2) · Chemistry
Match List - I with List - II.
\(\begin{array}{ll}
\text{List - I} & \text{List - II} \\
\text{Reaction} & \text{Type of redox reaction} \\
\text{(A) } \mathrm{TiCl}_4 & \text{(I) } \mathrm{e}^2, \mathrm{t}_2^0 \\
\text{(B) } \left[\mathrm{FeO}_4\right]^{2-} & \text{(II) } e^4, t_2^3 \\
\text{(C) } \left[\mathrm{FeCl}_4\right]^{-} & \text{(III) } e^0, t_2^0 \\
\text{(D) } \left[\mathrm{CoCl}_4\right]^{2-} & \text{(IV) } \mathrm{e}^2, \mathrm{t}_2^3
\end{array}\)
Choose the correct answer from the options given below :
- A(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- B(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- Correct answerC(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- D(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
Hence, the correct answer is option: 'C'.