Q13 / 90 · JEE Main 2024 (06 Apr Shift 2) · Chemistry

Match List - I with List - II. \(\begin{array}{ll} \text{List - I} & \text{List - II} \\ \text{Reaction} & \text{Type of redox reaction} \\ \text{(A) } \mathrm{TiCl}_4 & \text{(I) } \mathrm{e}^2, \mathrm{t}_2^0 \\ \text{(B) } \left[\mathrm{FeO}_4\right]^{2-} & \text{(II) } e^4, t_2^3 \\ \text{(C) } \left[\mathrm{FeCl}_4\right]^{-} & \text{(III) } e^0, t_2^0 \\ \text{(D) } \left[\mathrm{CoCl}_4\right]^{2-} & \text{(IV) } \mathrm{e}^2, \mathrm{t}_2^3 \end{array}\) Choose the correct answer from the options given below :

  • A
    (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  • B
    (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  • Correct answer
    C
    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  • D
    (A)-(I), (B)-(III), (C)-(IV), (D)-(II)

Hence, the correct answer is option: 'C'.

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