Q44 / 180 · JIPMER 2016 · Chemistry

Magnetic moment of $\left[\mathrm{Ti}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{4+}$, $\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ and $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ can be represented as $X, Y$ and $Z$. They are in order of

  • Correct answer
    A
    $X \lt Z \lt Y$
  • B
    $Z \lt Y \lt X$
  • C
    $X \lt Y \lt Z$
  • D
    $Z \lt Y \lt X$

Solution

$\begin{aligned} \mathrm{X}=[\mathrm{Ti} & \left.\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{4+}, \mathrm{E} \cdot \mathrm{C} \text { of } \mathrm{Ti}^{4+}=3 d^{\circ} \\ n & =0 \\ \mu_B & =0 \\ Y & =\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}, \mathrm{E} \cdot \mathrm{C} \text { of } \mathrm{Mn}^{+2}=3 d^5 \\ n & =3 \\ \mu_B & =3.87 \mathrm{BM} \\ \mathrm{Z} & =\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \mathrm{E} \cdot \mathrm{C} \text { of } \mathrm{Cr}^{3+}=3 d^3 \\ n & =3 \\ \mu_B & =3.87 \mathrm{BM}\end{aligned}$ Hence, the correct order of magnetic moment of $X, Y, Z$ is $X \lt Z \lt Y$

Hence, the correct answer is option: 'A'.

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