Let $A=\left[\begin{array}{ccc}0 & 0 & -1 \\ 0 & -1 & 0 \\ -1 & 0 & 0\end{array}\right], B=\left[\begin{array}{lll}0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1\end{array}\right]$ then $\left(A^{-1} B\right)^{-1}+$ $\left(\mathrm{AB}^{-1}\right)^{-1}=$

• A

  $\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & 2\end{array}\right]$
• Correct answer
  B

  $\left[\begin{array}{ccc}0 & -2 & 0 \\ 0 & 0 & -2 \\ -2 & 0 & 0\end{array}\right]$
• C

  $\left[\begin{array}{ccc}-2 & 0 & 0 \\ 0 & 0 & -2 \\ 0 & -2 & 0\end{array}\right]$
• D

  $\left[\begin{array}{ccc}0 & 0 & -2 \\ -2 & 0 & 0 \\ 0 & -2 & 0\end{array}\right]$

Hence, the correct answer is option: 'B'.