If $\Delta_{\mathrm{r}}=\left|\begin{array}{cc}\frac{1}{3 \mathrm{r}-2} & \frac{2}{3 \mathrm{r}-5} \\ 0 & \frac{3}{3 \mathrm{r}+1}\end{array}\right|$, then $\sum_{\mathrm{r}=1}^{33} \Delta_{\mathrm{r}}=$

• Correct answer
  A

  $0.99$
• B

  $0.33$
• C

  $0.66$
• D

  $0.55$

Hence, the correct answer is option: 'A'.