Let the area of the triangle with vertices A1,α,Bα,0 and C0,α be 4 sq. units. If the points α,-α,-α,α and α^2,β are collinear, then β is equal to

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MARKS Content Team · Accepted Answer

Correct answer: (C) -64. Given, the area of the triangle with vertices A1,α,Bα,0 and C0,α be 4 sq. units Now applying formula for area we get, 1/2 α 0 1 1 α 1 0 α 1 =±4 ⇒α=±8 Now given points will be 8,-8,-8,8,64,β OR -8,8,8,-8,64,β Given above points are collinear, so their slope will be equal, so slope=(8+8)/(-8-8)=-1 ⇒(β-8)/(64+8)=-1 ⇒β=-64

Let the area of the triangle with vertices $A (1, α), B (α, 0)$ and $C (0, α)$ be $4$ sq. units. If the points $(α, - α), (- α, α)$ and $(α^{2}, β)$ are collinear, then $β$ is equal to

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Relevant Questions

Let the area of the triangle with vertices A1,α,Bα,0 and C0,α be 4 sq. units. If the points α,-α,-α,α and α2,β are collinear, then β is equal to

Solution

Relevant Questions

Let the area of the triangle with vertices $A (1, α), B (α, 0)$ and $C (0, α)$ be $4$ sq. units. If the points $(α, - α), (- α, α)$ and $(α^{2}, β)$ are collinear, then $β$ is equal to