Let e be the eccentricity of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$. If $a=5, b=4$ and the equation of the normal drawn at one end of the latus rectum that lies in the first quadrant is $l x+m y=27$, then $l+m=$

• A

  $\frac{3}{e}$
• B

  $\frac{3}{2 e}$
• Correct answer
  C

  $\frac{6}{e}$
• D

  $\frac{1}{e}$

Hence, the correct answer is option: 'C'.