Q88 / 150 · JEE Main 2006 · Mathematics
Let $C$ be the circle with centre $(0,0)$ and radius 3 units. The equation of the locus of the mid points of the chords of the circle $C$ that subtend an angle of $\frac{2 \pi}{3}$ at its centre is
- A$x^2+y^2=\frac{3}{-}$
- B$x^2+y^2=1$
- C$x^2+y^2=\frac{27}{4}$
- Correct answerD$x^2+y^2=\frac{9}{4}$
Solution
$\cos \frac{\pi}{3}=\frac{\sqrt{h^2+k^2}}{3} \Rightarrow h^2+k^2=\frac{9}{4}$
Hence, the correct answer is option: 'D'.