Let $\bar{a}, \bar{b}, \bar{c}$ be such that $\bar{a} \neq \bar{o}, \bar{b} \neq \bar{o}, \bar{a} \times \bar{c}=\bar{b}$ and $\bar{b} \times \bar{c}=\bar{a}$. Then

• A

  $|\bar{c}|=|\bar{b}|$
• B

  $|\bar{a}|=|\bar{c}|$
• Correct answer
  C

  $|\bar{b}|=|\bar{a}|$
• D

  $\bar{c}=\bar{o}$

Hence, the correct answer is option: 'C'.