If $\mathrm{A}=(0,4,-3), \mathrm{B}=(5,0,12)$ and $\mathrm{C}=(7,24,0)$, then $\lfloor\mathrm{BAC}=$

• A

  $60^{\circ}$
• B

  $\operatorname{Cos}^{-1}\left(\frac{16}{\sqrt{13}}\right)$
• C

  $\operatorname{Cos}^{-1}\left(\frac{13}{38}\right)$
• Correct answer
  D

  $90^{\circ}$

Hence, the correct answer is option: 'D'.