Q113 / 200 · TS EAMCET 2001 · Mathematics

Let $f: R \rightarrow R$ be defined by $f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \\ x^2, & -1 < x < 1 \\ 2-x, & x \geq 1\end{array}\right.$ Then the value of $f(-1.75)+f(0.5)+f(1.5)$ is

  • A
    $0$
  • Correct answer
    B
    $1$
  • C
    $2$
  • D
    $-1$

Solution

$\begin{aligned} & f(-1.75)+f(0.5)+f(1.5) \\ &=(-1.75+2)+(0.25)+(2-1.5) \\ &=0.25+0.25+0.5 \\ &=1\end{aligned}$

Hence, the correct answer is option: 'B'.

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