Q113 / 200 · TS EAMCET 2001 · Mathematics
Let $f: R \rightarrow R$ be defined by
$f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \\ x^2, & -1 < x < 1 \\ 2-x, & x \geq 1\end{array}\right.$
Then the value of $f(-1.75)+f(0.5)+f(1.5)$ is
- A$0$
- Correct answerB$1$
- C$2$
- D$-1$
Solution
$\begin{aligned} & f(-1.75)+f(0.5)+f(1.5) \\ &=(-1.75+2)+(0.25)+(2-1.5) \\ &=0.25+0.25+0.5 \\ &=1\end{aligned}$
Hence, the correct answer is option: 'B'.