Q97 / 225 · JEE Main 2002 · Mathematics

Let $f(x)=4$ and $f^{\prime}(x)=4$. Then $\operatorname{Lim}_{x \rightarrow 2} \frac{x f(2)-2 f(x)}{x-2}$ is given by

  • A
    2
  • B
    -2
  • Correct answer
    C
    -4
  • D
    3

Solution

We have, $\operatorname{Lim}_{x \rightarrow 2} \frac{x f(2)-2 f(x)}{x-2}\left(\frac{0}{0}\right)=\operatorname{Lim}_{x \rightarrow 2} f(2)-2 f^{\prime}(x)=f(2)-2 f^{\prime}(2)=4-2 \times 4=-4$

Hence, the correct answer is option: 'C'.

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