Q97 / 225 · JEE Main 2002 · Mathematics
Let $f(x)=4$ and $f^{\prime}(x)=4$. Then $\operatorname{Lim}_{x \rightarrow 2} \frac{x f(2)-2 f(x)}{x-2}$ is given by
- A2
- B-2
- Correct answerC-4
- D3
Solution
We have, $\operatorname{Lim}_{x \rightarrow 2} \frac{x f(2)-2 f(x)}{x-2}\left(\frac{0}{0}\right)=\operatorname{Lim}_{x \rightarrow 2} f(2)-2 f^{\prime}(x)=f(2)-2 f^{\prime}(2)=4-2 \times 4=-4$
Hence, the correct answer is option: 'C'.