Q36 / 118 · NTA Abhyas (JEE Main) 2020 · Mathematics · Sequences and Series

Let α and β be two numbers where α<β . The geometric mean of these numbers exceeds the smaller number α by 12 and the arithmetic mean of the same numbers is smaller by 24 than the larger number β, then the value of |β-α| is

Correct answer: 48

Solution

Given, α and β be two number where α<β .

∵   The geometric mean of these numbers exceeds the smaller number α by 12 .

i.e. αβ=α+12 .....(i)

And the arithmetic mean of the same numbers is smaller by 24 than the number β .

i.e. α+β2=β-24 ......(ii)

By solving Equations. (i) and (ii), we get

α=6, β=54

∴        β-α=54-6=48

Hence, the correct answer is 48.

More Sequences and Series Questions