If 12020+22019+32018+.........+20201=2020×2021×k, then the value of k/100 is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: 3.37. t_r=r2021-r S=∑r=12020t_r=∑r=12020r2021-r =2021∑r=12020r-∑r=12020r^2 =2021×(2020×2021)/2-(2020×2021×4041)/6 =(2021×2020)/22021-4041/3 =(2020×2021)/2×674 =2020×2021×337 ⇒k=337⇒k/100=3.37

If $(1) (2020) + (2) (2019) + (3) (2018) + . . . . . . . . . + (2020) (1) = 2020 \times 2021 \times k,$ then the value of $\frac{k}{100}$ is equal to

Solution

More Sequences and Series Questions

If 12020+22019+32018+.........+20201=2020×2021×k, then the value of k100 is equal to

Solution

More Sequences and Series Questions

If $(1) (2020) + (2) (2019) + (3) (2018) + . . . . . . . . . + (2020) (1) = 2020 \times 2021 \times k,$ then the value of $\frac{k}{100}$ is equal to