Q37 / 105 · NTA Abhyas (JEE Main) 2020 · Mathematics · Three Dimensional Geometry

Let A→ be a vector parallel to the line of intersection of the planes P1 and P2. The plane P1 is parallel to the vectors 2j^+3k^ and 4j^-3k^ while plane P2 is parallel to the vectors j^-k^ and i^+j^. The acute angle between A→ and 2i^+j^-2k^ is

  • A
    π6
  • Correct answer
    B
    π4
  • C
    π3
  • D
    5π12

Solution

Let, a→=2j^+3k^
b→=4j^-3k^
c→=j^-k^
d→=i^+j^
e→=2i^+j^-2k^
A normal vector perpendicular to the plane P1 is a→×b→
A normal vector perpendicular to the plane P2 is c→×d→
A vector parallel to the line of intersection is a→×b→×c→×d→=k^-j^
Let, θ be the acute angle between them then,
cos⁡θ=A→·e→A→e→=-32×3=12
⇒θ=π4

Hence, the correct answer is option: 'B'.

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