Let a, b, c∈ℝ be such that 2a+3b+6c=0 and g(x) be the antiderivative of f(x)=ax^2+bx+c. If the slopes of the tangents drawn to the curve y=g(x) at…

Question

Let a, b, c∈ℝ be such that 2a+3b+6c=0 and g(x) be the antiderivative of f(x)=ax^2+bx+c. If the slopes of the tangents drawn to the curve y=g(x) at (1,g(1)) and (2,g(2)) are equal, then

MARKS Content Team · Accepted Answer

Correct answer: (B) a/6=b/(-18)=c/7. Slopes of tangent of the function gx at x=1 & x=2 implies that f1=f2. ⇒a+b+c=4a+2b+c ⇒3a+b=0 ...i And 2a+3b+6c=0 ...ii (Given) Solving equations i & ii by cross-multiplication method we get, a/6=b/(-18)=c/7.

Let $a, b, c \in ℝ$ be such that $2 a + 3 b + 6 c = 0$ and $g (x)$ be the antiderivative of $f (x) = a x^{2} + b x + c .$ If the slopes of the tangents drawn to the curve $y = g (x)$ at $(1, g (1))$ and $(2, g (2))$ are equal, then

Solution

Relevant Questions

Let a, b, c∈ℝ be such that 2a+3b+6c=0 and g(x) be the antiderivative of f(x)=ax2+bx+c. If the slopes of the tangents drawn to the curve y=g(x) at (1,g(1)) and (2,g(2)) are equal, then

Solution

Relevant Questions

Let $a, b, c \in ℝ$ be such that $2 a + 3 b + 6 c = 0$ and $g (x)$ be the antiderivative of $f (x) = a x^{2} + b x + c .$ If the slopes of the tangents drawn to the curve $y = g (x)$ at $(1, g (1))$ and $(2, g (2))$ are equal, then