Q111 / 160 · TS EAMCET 2025 (03 May Shift 2) · Mathematics
If the point $\mathrm{P}\left(x_1, y_1\right)$ lying on the curve $y=x^2-x+1$ is the closest point to the line $y=x-3$ then the perpendicular distance from P to the line $3 x+4 y-2=0$ is
- A$\frac{16}{5}$
- B4
- Correct answerC1
- D$\frac{7}{5}$
Hence, the correct answer is option: 'C'.