Q30 / 54 · JEE Advanced 2018 (Paper 1) · Mathematics

Let a→ and b→ be two unit vectors such that a→.b→=0. For some x,y∈R, let c→=xa→+yb→+a→×b→. If c→=2 and the vector c→ is inclined at the same angle α to both a → and b → , then the value of 8 cos 2 α is

Correct answer: 3

Solution

c→=xa→+yb→+a→×b→
c→.a→=x and x=2cos⁡α
c→.b→=y and y=2cos⁡α
Also, a→×b→=1
∴  c→=2cos α ⁡a→+b→+a→ ×b→
c→2=4cos2⁡αa→+b→2+a→×b→2+4cos⁡αa→+b→.a→×b→
4=8cos2⁡α+1
8cos2⁡α=3

Hence, the correct answer is 3.

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