Q42 / 66 · JEE Advanced 2007 (Paper 2) · Mathematics
Let $f(x)=\frac{x^2-6 x+5}{x^2-5 x+6}$.


- Correct answerAA-p; B-q; C-q; D-p
- BA-r; B-s; C-q; D-r
- CA-s; B-p; C-q; D-p
- DA-r; B-q; C-p; D-r
Solution
$$
f(x)=\frac{(x-1)(x-5)}{(x-2)(x-3)}
$$
The graph of $f(x)$ is shown

(A) If $-1 < x < 1 \Rightarrow 0 < f(x) < 1$ (B) If $1 < x < 2 \Rightarrow f(x) < 0$ (C) If $3 < x < 5 \Rightarrow f(x) < 0$ (D) If $x>5 \Rightarrow 0 < f(x) < 1$

(A) If $-1 < x < 1 \Rightarrow 0 < f(x) < 1$ (B) If $1 < x < 2 \Rightarrow f(x) < 0$ (C) If $3 < x < 5 \Rightarrow f(x) < 0$ (D) If $x>5 \Rightarrow 0 < f(x) < 1$
Hence, the correct answer is option: 'A'.