$\beta-emission$ is always accompanied by

• A

  formation of antineutrino and $\alpha$ -particle
• B

  emission of $\alpha$ -particle and $\gamma$ -ray
• Correct answer
  C

  formation of antineutrino and $y$ -ray
• D

  formation of antineutrino and positron

Solution

During the $\beta$ -emission, a neutron gets converted into a proton along with the formation of antineutrino and electron.

Hence, the correct answer is option: 'C'.