Q2 / 160 · WBJEE 2012 · Chemistry

${ }_{11} Na $^{24}$ is radioactive and it decays to

  • A
    ${ }_{9} \mathrm{F}^{20}$ and $\alpha$ -particles
  • B
    ${ }_{13} \mathrm{Al}^{24}$ and positron
  • C
    ${ }_{11} \mathrm{Na}^{23}$ and neutron
  • Correct answer
    D
    ${ }_{12} \mathrm{Mg}^{24}$ and $\beta$ - particles

Solution

$_{11} \mathrm{Na}^{24} \longrightarrow _{12} \mathrm{Mg}^{24}+_{-1}\beta^{0}$

Hence, the correct answer is option: 'D'.

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