Q95 / 225 · JEE Main 2002 · Mathematics

$\int_0^{\sqrt{2}}\left[x^2\right] d x$ is

  • A
    $2-\sqrt{2}$
  • B
    $2+\sqrt{2}$
  • Correct answer
    C
    $\sqrt{2}-1$
  • D
    $\sqrt{2}-2$

Solution

$\int_1^0\left[x^2\right] d x+\int_1^{\sqrt{2}}\left[x^2\right] d x=0+\int_1^{\sqrt{2}} d x=\sqrt{2}-1$

Hence, the correct answer is option: 'C'.

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