In the Young’s double slit experiment the intensity of light at a point on the screen where the path difference is $\lambda$ is $K,$ ( $\lambda$ being the wave length of light used). The intensity at a point where the path difference is $\frac{\lambda }{4},$ will be:

• A

  $K$
• B

  $\frac{K}{4}$
• Correct answer
  C

  $\frac{K}{2}$
• D

  Zero

Hence, the correct answer is option: 'C'.