Q132 / 180 · NEET 2015 (Phase 2) · Physics

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:

A
$\frac{9}{4}$
B
$\frac{27}{5}$
Correct answer
C
$\frac{5}{27}$
D
$\frac{4}{9}$

Solution

\frac{1}{λ_{1}} = R_{e} (\frac{1}{1^{2}} - \frac{1}{2^{2}})

\frac{1}{λ_{2}} = R_{e} (\frac{1}{2^{2}} - \frac{1}{3^{2}})

\frac{λ_{1}}{λ_{2}} = \frac{5}{27}

Hence, the correct answer is option: 'C'.

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