Q128 / 180 · NEET 2017 · Physics

The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is_____.

A
$2$
B
$1$
Correct answer
C
$4$
D
$0.5$

Solution

For last Balmer series,
$\frac{1}{λ_{b}} = R [\frac{1}{2^{2}} - \frac{1}{\infty^{2}}]$
$λ_{b} = \frac{4}{R}$
For last Lyman series,
$\frac{1}{λ_{l}} = R [\frac{1}{1^{2}} - \frac{1}{\infty^{2}}]$
$λ_{l} = \frac{1}{R}$
$\frac{λ_{b}}{λ_{l}} = \frac{\frac{4}{R}}{\frac{1}{R}}$
$\frac{λ_{b}}{λ_{l}} = 4$
Hence this is the correct answer.

Hence, the correct answer is option: 'C'.

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