Q12 / 125 · BITSAT 2020 · Chemistry

In the reaction $2 \mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$, the change in hybridisation is from

  • Correct answer
    A
    $s p^{3} d$ to $s p^{3}$ and $s p^{3} d^{2}$
  • B
    $s p^{3} d$ to $s p^{2}$ and $s p^{3}$
  • C
    $s p^{3} d$ to $s p^{3} d^{2}$ and $s p^{3} d^{3}$
  • D
    $s p^{3} d^{2}$ to $s p^{3}$ and $s p^{3} d$

Solution

$2 \mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$ $\uparrow s p^{3} d \quad \uparrow s p^{3} \quad \uparrow s p^{3} d^{2}$

Hence, the correct answer is option: 'A'.

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