Q91 / 120 · VITEEE 2006 · Physics
In the presence of magnetic field ' $B$ ' and electric field ' $E$ ', the total force on a moving charged particle is
- A$\overrightarrow{\mathrm{F}}=\overrightarrow{\mathrm{v}}[(\overrightarrow{\mathrm{q}} \times \overrightarrow{\mathrm{B}})+\overrightarrow{\mathrm{E}}]$
- B$\overrightarrow{\mathrm{F}}=\mathrm{q}[(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{E}})+\overrightarrow{\mathrm{B}}]$
- Correct answerC$\overrightarrow{\mathrm{F}}=\mathrm{q}[(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})+\overrightarrow{\mathrm{E}}]$
- D$\overrightarrow{\mathrm{F}}=\overrightarrow{\mathrm{B}}[(\overrightarrow{\mathrm{q}} \times \overrightarrow{\mathrm{E}})+\overrightarrow{\mathrm{v}}]$
Solution
Lorentz force on a charged particle in presence of magnetic and electic field is
$\begin{array}{l}
\overrightarrow{\mathrm{F}}=\overrightarrow{\mathrm{F}}_{\mathrm{e}}+\overrightarrow{\mathrm{F}}_{\mathrm{m}} \\
\Rightarrow \overrightarrow{\mathrm{F}}=\mathrm{q} \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})
\end{array}$
Hence, the correct answer is option: 'C'.